Tensor Symmetry
Exercise PLAN-311
primary source nl only. Current content-bound mathematical second pass accepted. No new Lean verification is claimed for this NL view.
Assumptions and conventions
- lambda has exactly two parts with lambda_1 at least lambda_2 at least zero.
- The determinant representation sends a unitary to its determinant; the degree-m symmetric power of C^2 has dimension m plus one.
Question
For the two-dimensional unitary group, the irreducible pieces appearing in tensor powers of C^2 are indexed by partitions lambda = (lambda_1, lambda_2) with two parts. Prove that the dimension of the piece associated with such a partition equals lambda_1 minus lambda_2 plus one, and explain how this follows both from the semistandard-tableau count and from the explicit description of the piece as a determinant power times a symmetric power.
Hint: mathematical route
The two-dimensional unitary irreducible piece for a two-part partition has dimension lambda_1 minus lambda_2 plus one, from both tableau counting and the determinant-times-symmetric-power form.
- The dimension is the number of two-letter semistandard tableaux of shape lambda.
- Columns are forced 1 over 2; only the lambda_1 minus lambda_2 extra first-row cells vary.
- The piece is a one-dimensional determinant power times a degree-m symmetric power.
- The degree-m symmetric power of C^2 has dimension m plus one, agreeing with the count.
Reference solution
Semistandard count: the dimension equals the number of semistandard Young tableaux of shape lambda with entries from the two-letter alphabet {1,2}, that is fillings weakly increasing along rows and strictly increasing down columns. In the two-row shape the two cells of any column must be 1 above 2, which is forced; the only freedom is in the first row, which has lambda_1 minus lambda_2 cells beyond the part covered by the second row, and those cells must be weakly increasing in {1,2}, so they are some number of 1s followed by 2s. The number of such choices is lambda_1 minus lambda_2 plus one, giving the dimension. Explicit description: the piece is isomorphic to the determinant representation raised to the power lambda_2, tensored with the degree-m symmetric power of C^2, where m equals lambda_1 minus lambda_2. The determinant factor is one-dimensional, so it does not change the dimension; the symmetric power of degree m of a two-dimensional space has dimension m plus one. Hence the dimension is m plus one equal to lambda_1 minus lambda_2 plus one, matching the tableau count. Both routes agree because tensoring by the one-dimensional determinant shifts the highest weight without changing dimension, and the symmetric power is exactly the semistandard content of the first-row freedom.
Assessment rubric
- States the dimension equals the number of two-letter semistandard tableaux of shape lambda (1 weight)
- Shows the columns are forced to be 1 over 2 and the only freedom is the lambda_1 minus lambda_2 extra first-row cells, giving lambda_1 minus lambda_2 plus one fillings (1 weight)
- Gives the determinant-power-times-symmetric-power description and notes the determinant factor is one-dimensional (1 weight)
- Concludes the symmetric power of degree lambda_1 minus lambda_2 has dimension lambda_1 minus lambda_2 plus one, matching the tableau count (1 weight)
Graph-grounded prerequisites
These are support/source anchors, not an automatically extracted theorem-dependency proof.
- Tensor networks (frozen curriculum anchor; see graph registry)
- Matrix analysis (frozen curriculum anchor; see graph registry)
Lean view and evidence boundary
No aligned Lean view has been admitted for this native core in this textbook checkpoint. This is not a claim that the underlying mathematics lacks a formal proof. Contributions must preserve this exact target contract and split.
Sources and provenance
- website/research/sources.json
leditzky-2025-repth-qit
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Authored support steps: 4. This is not measured graph distance or model difficulty.